Десятилетний мальчик поймал крупную рыбу и побил десятилетний рекорд

· · 来源:dev资讯

Node *temp = curr;

思路:找「右侧第一个 ≤ cur」的元素 → 弹出所有 cur 的元素,栈顶即为折扣。最终价格 = cur - 折扣(有则)或 cur(无则)。

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